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A positive resolution of the gap-entropy conjecture

arXiv cs.AI / cs.LG / cs.CLby P. M. Aronow ()1 min read2 · 1 read
AI summary · glm-5.3-flashSummaries by Vani AI

New proof resolves the gap-entropy conjecture for Gaussian bandits, bounding optimal best-arm identification samples by H(log(1/delta)+Ent(I)) up to constants.

A paper proves the gap-entropy conjecture for fixed-confidence best-arm identification with independent unit-variance Gaussian arms, means in [0,1], and a unique optimal arm. It shows the optimal expected sample count, averaged over arm-label permutations, is within absolute constant factors of H(log(1/delta)+Ent(I)), where H sums squared gaps and Ent(I) is the instance's gap-entropy. It also gives an instance-independent algorithm bounded by a constant multiple of this quantity plus a g^-2 loglog(e^e/g) term for the smallest gap g.

Key facts
  • Positive proof of the gap-entropy conjecture for Gaussian best-arm identification.
  • Optimal sample complexity within constant factors of H(log(1/delta)+Ent(I)).
  • Instance-independent algorithm adds a g^-2 loglog term.
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From the original article

1 min read at arxiv.org

We prove the gap-entropy conjecture for fixed-confidence best-arm identification with independent unit-variance Gaussian arms, means in $[0,1]$, and a unique optimal arm. For each suboptimal arm $i$, let $Δ_i=μ_*-μ_i$ be its gap from the optimal mean, and write $H=\sum_{i\ne *}Δ_i^{-2}$. Let $p_r$ be the fraction of $H$ contributed by arms with $2^{-(r+1)} 0} p_r\log(1/p_r)$.

arXiv cs.AI / cs.LG / cs.CL

By P. M. Aronow · arxiv.org

Read the full article at arXiv cs.AI / cs.LG / cs.CL

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